How do you solve $(2^6 times 2^3)/(2^n) = 2^5$ ?

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Answer 1 · 2017-05-25T11:45:04

$n=4$

First multiply both sides by $color(green)2^color(green)n$ :

$(2^6 times 2^3)/(2^n)$ $times$ $color(green)2^color(green)n$ $=$ $2^5$ $times$ $color(green)2^color(green)n$

This will remove $2^n$ from the LHS :

$(2^6 times 2^3)/cancel(2^n)$ $times$ $cancel(2^n)$ $=$ $2^5$ $times$ $color(green)2^color(green)n$

Second add the exponents of similar bases :

$2^(6+3)$ $=$ $2^(5+n)$

$=>$ $2^9$ $=$ $2^(5+n)$

Third use the $"Base Rule"$ :

i.e. $9= 5 + n$

$:.$ $n=4$

How do you solve (2^6 times 2^3)/(2^n) = 2^5(2^6 times 2^3)/(2^n) = 2^5?