Question #f8198

1 Answer
Altrigeos
May 19, 2017

See Below

Explanation:

Phythagorean Identity:
#sin^2(theta)+cos^2(theta)=1#
#[sin^2(theta)+cos^2(theta)=1]/sin^2(theta)#
#cot^2(theta)+1=csc^2(theta)#

Use it to solve the identity:

#1+csc^2(theta)cos^2(theta)#
#1+cos^2(theta)/sin^2(theta)#
#1+cot^2(theta)#
#csc^2(theta)=RHS#

QED

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