Question #cdb75

1 Answer
loucololosse
May 18, 2017

700J

Explanation:

In general:
![www.uqac.ca)
The work is defined by this equation:
#W=F*S#
S is the distance
F is the force

Between the distance and the force is a "dot product" or a "scalar product". That means that we only take the force that is put to make the object move in the direction it's moving. The value of the work can be written:
#W=FScos(theta)#
#theta# is the shortest angle between the force and the distance

For your situation:
#W=(350)(2)cos(0)#
#W=700#J

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