Question #2f4ab

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May 15, 2017

Answer: #f'(x)=sqrt(x/4)#

Explanation:

Find inverse of #f(x)=4x^2#

Note that #f(x)# is same as #y#

So, #y=4x^2#

To find the inverse, we flip #x# and #y# in the original equation:
#x=4y^2#

Now, we can simply solve for #y# as for a normal equation:
#x/4=y^2#
#y=sqrt(x/4)#
or
#f'(x)=sqrt(x/4)#
since we use #f'(x)# to indicate inverse functions

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