How do you solve $x^ { 2} - 20x + 100= 28$ ?

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Answer 1 · 2017-05-14T18:48:05

$S = {10 +- 2sqrt7}$

$x^2 - 20x + 100 = 28$
Factorize
$<=> (x-10)^2 = 28$
$<=> x-10 = sqrt28$ or $x-10 = -sqrt28$
$<=> x=10+2sqrt7$ or $x=10-2sqrt7$

How do you solve x^ { 2} - 20x + 100= 28x^ { 2} - 20x + 100= 28?