How do you solve #4y + \frac { 2y - 3} { 2} = 8#?

1 Answer
Y
May 14, 2017

Multiply both sides by 2, then simplify
Answer: #y=1.9#

Explanation:

Solve #4y+(2y-3)/2=8#

First we want to multiply the entire equation by #2# to eliminate the fraction:
#2(4y+(2y-3)/2=8)#
#8y+2y-3=16#

We can add #3# to both sides to move the constants to one side:
#8y+2y-3+3=16+3#

Now we can combine like-terms:
#10y=19#

Finally, we divide both sides by #10# to isolate #y#:
#(10y)/10=19/10#
#y=1.9#

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