Question #f92a2

1 Answer
Simon Moore
May 10, 2017

I don't understand the structure you've written...

Explanation:

What is the "I CH3"? Is the "I" a bond, or is it supposed to be iodine? Both of those would result in a pentavalent carbon in position 4, so that isn't possible.

If you can clarify exactly what "I CH3" means I can probably help.

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