What is the standard form of $y= (x-14)(x-2)$ ?

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Answer 1 · 2017-05-02T14:30:21

$y=x^2-16x+28$

To find the standard form from this form (factored form), we simply multiply the sets of brackets. If you're unsure how to do that, see this link

$y=(x-14)(x-2)$
$y=x^2-14x-2x+28$
Then collect the x terms, to get:
$y=x^2-16x+28$

Answer 2 · 2017-05-02T14:31:28

See the entire solution process below:

To get to the standard form of the equation you must multiply the two terms on the right side of the equation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$y = (color(red)(x) - color(red)(14))(color(blue)(x) - color(blue)(2))$ becomes:

$y = (color(red)(x) xx color(blue)(x)) - (color(red)(x) xx color(blue)(2)) - (color(red)(14) xx color(blue)(x)) + (color(red)(14) xx color(blue)(2))$

$y = x^2 - 2x - 14x + 28$

We can now combine like terms:

$y = x^2 + (-2 - 14)x + 28$

$y = x^2 + (-16)x + 28$

$y = x^2 - 16x + 28$

What is the standard form of y= (x-14)(x-2) y= (x-14)(x-2) ?