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Question #1ef6f

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Apr 29, 2017

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In first case, because #L = lambda_1/2#, the fund freq is #f_1 = v/ lambda_1 = v/(2L)#

In second case, because #(3L)/4 = lambda_2/4#, the fund freq is #f_2 = v/ lambda_2 = v/(3L)#

So #f_2 = 2/3 f_1 = 260 Hz#

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