Two non collinear position vectors $\to a & \to b$ $veca & vecb$ are inclined at an angle $\frac{2 π}{3}$ $(2pi)/3$ ,where $∣ ∣ \to a ∣ ∣ = 3 & ∣ ∣ ∣ \to b ∣ ∣ ∣ = 4$ $|veca|=3 & |vecb|=4$ . A point P moves so that $- - \to O P = (e^{t} + e^{- t}) \to a + (e^{t} - e^{- t}) \to b$ $vec(OP)=(e^t+e^-t)veca +(e^t-e^-t)vecb$ . The least distance of P from origin O is $\sqrt{2} \sqrt{\sqrt{p} - q}$ $sqrt2sqrt(sqrtp-q)$ then p+q =?

2 confused questions ?