Question #42f7e

1 Answer
shr
Apr 26, 2017

Solving for x is simply when # y = 0, #in the equation you gave, the right hand side can only evaluate to zero if and only if the numerator, #x + 1 = 0#. The denominator cannot equal to 0, as that would produce an undefined result. Thus you solve:

#x + 1 = 0#
#x = -1#

#f(-1) = 0#
#:. x = -1# is a solution that satisfies the equation.

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