How do you solve the system of equations #x+3y=-7# and #-x-3y=1#?

1 Answer
shr
Apr 25, 2017

#No # #solution#

Explanation:

#1. x + 3y = -7#
#2.-x-3y = 1#

Consider #1.#
#x = -7 - 3y#

Substitute the value of x from #1.# to #2.#:
#-(-7-3y) -3y = 1#
#7 + 3y - 3y = 1#
#7 = 1#

This means that there is no solution to the system, thus these lines must be parallel. If you convert both #1.# and #2.# to the form #y = mx + b#, you will see the #m# values, or the slope of both lines is the same, thus they will never intersect, hence no solution.

Related questions
Impact of this question
1289 views around the world
You can reuse this answer
Creative Commons License