How do you solve the system of equations #x+3y=-7# and #-x-3y=1#?

1 Answer
shr
Apr 25, 2017

#No # #solution#

Explanation:

#1. x + 3y = -7#
#2.-x-3y = 1#

Consider #1.#
#x = -7 - 3y#

Substitute the value of x from #1.# to #2.#:
#-(-7-3y) -3y = 1#
#7 + 3y - 3y = 1#
#7 = 1#

This means that there is no solution to the system, thus these lines must be parallel. If you convert both #1.# and #2.# to the form #y = mx + b#, you will see the #m# values, or the slope of both lines is the same, thus they will never intersect, hence no solution.

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