Question #bb541
1 Answer
Apr 24, 2017
Explanation:
#"using the method of "color(blue)"completing the square"#
#"to complete the square"# add
#(1/2"coefficient of the x-term")^2" to " x^2+10x# Since we are adding on a value which is not there we must also subtract it.
#"that is add/subtract " (10/2)^2=color(red)(25)#
#rArry=(x^2+10xcolor(red)(+25))color(red)(-25)-3#
#color(white)(rArry)=(x+5)^2-28larrcolor(red)" in vertex form"#
