What is the equation for the line that is parallel to $3x-2y=-6$ and passes through the point $(8, 16)$ ?

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Answer 1 · 2017-04-24T20:05:55

$y=(3/2)x+4$
graph{(3/2)x+4 [-0.89, 35.18, 9.42, 27.44]}

$3x-2y=-6$
$-2y=-3x-6$
$y=(3/2)x+3$

The slope $(3/2)$ is the same because the line is parallel. Plug the in numbers to find $b$ , which is the y-intercept of the new line.

$y=(3/2)x+b$
$16=(3/2)8+b$
$16=12+b$
$4=b$

So the new equation is...
$y=(3/2)x+4$

What is the equation for the line that is parallel to 3x-2y=-63x-2y=-6 and passes through the point (8, 16)(8, 16)?