How do you simplify (\frac { 2x ^ { 7} y ^ { 8} } { 6x y ^ { 9} } ) ^ { 3}(2x7y86xy9)3?

3 Answers
Margarita Kisyova
Apr 22, 2017

See below.

Explanation:

1st you have to do everything inside the bracket and then cube it
2x^7y^82x7y8 ÷ 6xy^96xy9
= 0.6x^6y^-10.6x6y−1 × 0.6x^6y^-10.6x6y−1 × 0.6x^6y^-10.6x6y−1
= 2x^182x18 y^-3y−3

I believe that this is correct!
I hope this will help you!

Barney V.
Apr 22, 2017

color(red)((x^18)/(27y^3)x1827y3

Explanation:

((2x^7y^8)/(6xy^9))^3(2x7y86xy9)3

:.=(2^3x^21y^24)/(6^3x^3y^27)

:.=(cancel8^color(red)1x^(21-3))/(cancel216^color(red)27y^(27-24))

:.color(red)(=(x^18)/(27y^3)

Tony B
Apr 22, 2017

(x^18)/(27y^3)

Explanation:

First consider the contents of the brackets.

2/(2xx3) xx(x xxx^6)/x xx(y^8)/(y^8xxy)

2/2xx1/3xx x/x xxx^6 xxy^8/y^8 xx1/y

1xx1/3xx1xx x^6xx1xx1/y

(x^6)/(3y)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Now put this back into the brackets

((x^6)/(3y))^3 = (x^18)/(27y^3)

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