A coffee maker which draws 13.5 A of current has been left on for 10 minutes. What is the net number of electrons that have passed through it?

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A coffee maker which draws 13.5 A of current has been left on for 10 minutes. What is the net number of electrons that have passed through it?

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Answer 1 · 2017-04-19T10:05:12

$5.0625 \cdot 10^{22}$ $5.0625*10^22$

Explanation:

net charge passed in 10 minutes : current(A) * time(sec)
$13.5 \cdot 10 \cdot 60 = 8100 C$ $13.5 * 10 * 60 = 8100 C$
an electron has $1.6 \cdot 10^{- 19} C$ $1.6*10^-19 C$ charge on it
number of electrons passed in 10 min : total charge / charge on electron
$= \frac{8100}{1.6 \cdot 10^{- 19}}$ $= 8100/(1.6*10^-19)$
$= 5.0625 \cdot 10^{22}$ $= 5.0625*10^22$ electrons

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A coffee maker which draws 13.5 A of current has been left on for 10 minutes. What is the net number of electrons that have passed through it?

1 Answer

Explanation:

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