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Question #0e146

1 Answer

Apr 19, 2017

1

Explanation:

First, you would substitute #cotx=cosx/sinx#, then you get the expression:

#sin^2x+sin^2xcot^2x=sin^2x+cancel(sin^2x)cos^2x/cancel(sin^2x)#

and you would simplify and get:

#sin^2x+cos^2x=1#

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