How do you solve 46- 4x = 4x ^ { 2}?

2 Answers
salamat
Apr 18, 2017

x = (-1 +- sqrt 47)/2

Explanation:

46 - 4x = 4x^2
4x^2 + 4x - 46 =0

reduce the equation by divide with 2
2x^2 + 2x - 23 = 0

2(x^2 + x ) -23 =0

2(x + 1/2)^2 -2(1/2)^2 -23 = 0

2(x + 1/2)^2 - 47/2 = 0

2(x + 1/2)^2 = 47/2

(x + 1/2)^2 = 47/4

x + 1/2 = +-sqrt(47/4) = +-sqrt47/2

x = -1/2 +-sqrt47/2 = (-1 +- sqrt 47)/2

Catherine T. Mohs
Apr 18, 2017

x=-1/2+-sqrt(47)/2

Explanation:

46-4x=4x^2
4x^2+4x-46=0
x=(-b+-sqrt(b^2-4ac))/(2a)
x=(-4+-sqrt(4^2-4*4*-46))/(2*4)
x=(-4+-sqrt(16+736))/(8)
x=(-4+-sqrt(752))/(8)
x=-1/2+-sqrt(47)/2

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