Question #35a5b

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Answer 1 · 2017-04-17T18:30:38

See below

#cosx+cosxtan^2x#

#=cosx+cosx(sin^2x/cos^2x)#

#=cosx+sin^2x/cosx#

#=cosx+(1-cos^2x)/cosx#

#=cos^2x/cosx+(1-cos^2x)/cosx#

#=1/cosx#

#=secx#

Answer 2 · 2017-04-17T19:52:09

See below

#cosx+cosxtan^2x#
#=cosx(1+tan^2x)#
#=cosxsec^2x#
#=secx#