What is the #x#-intercept of the line that contains the points #(-4, 1)# and #(-7, 2)# in the standard #(x, y)# coordinate plane?
1 Answer
Apr 17, 2017
(see below)
Explanation:
Find the equation of the line:
-
Find the gradient using
#dy/dx#
#(1-2)/(-4+7) = -1/3# -
Take 1 coordinate point and use
#y-y_1 = m (x-x_1)# to find the equation of the line
#y-1 = -1/3 ( x - (-4) )#
#y-1 = -1/3x - 4/3#
#y = -1/3x - 1/3# -
substitute 0 into y to find the x-intercept.
