What is the mole fraction of $N a C l$ $NaCl$ if 117 g of it is dissolved in 180 mL of water?

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Answer 1 · 2017-04-17T00:25:04

16.83 M

For this we'd use the following equation:

$M o l a r i t y = \frac{N}{V}$ $Molarity = N/V$

N meaning the grams/moles and V meaning the volume in Liters.

So first we find the molar mass of NaCl to be 58.44 grams.

we can setup this proportion to find the 'n'

$\frac{x}{117} = \frac{1}{58.44}$ $x/117= 1/58.44$

$\frac{177}{58.44} =$ $177/58.44=$ 3.03

Now we convert the 180 mL to L, so .180 L.

Finally,

$M = \frac{3.03}{.180}$ $M= 3.03/.180$

M=16.83

The molarity (mole fraction) is 16.83 Molar

What is the mole fraction of NaClNaCl if 117 g of it is dissolved in 180 mL of water?