The water level in a plastic pool changed by -8 gallons each hour due to a small hole in the bottom. After 6 hours, the pool contained 132 gallons. How much water was in the pool originally?

1 Answer
Deep
Apr 16, 2017

180 gallons

Explanation:

the water level reduces by 8 gallons each hour due to the hole , so in 6 hours the water level will reduce by # 6*8 # = 48 gallons .
thus , 48 gallons left the pool in 6 hours , so this 48 gallons was initially in the pool .
therefore , to calculate total water initially present in the pool add the water that left the pool in 6 hours and the water that is left in the pool after 6 hours : # 132 + 48 # = 180 gallons.

Related questions
Impact of this question
1973 views around the world
You can reuse this answer
Creative Commons License