How do you graph the solution to #4+ 2x < 8#?

1 Answer
Andrés G.
Apr 15, 2017

plot

Explanation:

Plot #f(x) = 2x + 4# which is a linear plot with #"slope" = 2#, and intersecting the y axis at #(0,4)#

graph{2x +4 [-8.52, 16.79, -0.28, 12.38]}

Then plot #g(x) = 8#, an horizontal line at #y = 8#.
graph{8*(x/x) [-4.59, 23.88, -1.05, 13.19]}

Plot both on the same plane and highlight the left-hand side intersection as it's a "#<#" inequality.

plot

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