How many grams of silver are needed to absorb 1.00 kJ of energy changing the temperature 33.0 C to 41.8°C?

1 Answer
I.F.M
Apr 14, 2017

473.5 grams

Explanation:

#q = mcDeltaT#

q = heat energy (joules)
m = mass (grams)
c = specific heat (#"Joules"/"gram * Celsius"#)
#DeltaT# = change in temperature

In this case:
q = 1 KJ = 1000 J
m = ?
c = 0.24
#DeltaT# = 41.8 - 33 = 8.8

#q = mcDeltaT#
1000 = (m)(0.24)(8.8)
1000 = (m)(2.112)
m = 473.5

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