How do you solve #-5( - 5v + 9) - 6v = 4( v - 6) - 9#?

1 Answer
Ryuu
Apr 13, 2017
  1. Expand brackets.
  2. Add like terms -> all like terms; some are on different sides of the equal sign.
  3. Solve for #v#.

In this case, #v=4/5#.

Explanation:

So first off, we expand the brackets.

#-5(-5v+9) -6v = 4(v-6) - 9#

#25v-45-6v = 4v-24 - 9#

Now we add like terms.

#19v-45 = 4v-33#

Now, we bring all like variables to one side of the equal sign, and the other variables on the other side.

#19v-4v = -33 + 45#

Again, we add like terms.

#15v = 12#

Finally, we isolate for the variable, #v#.

#(15v)/15 = 12/15#

#v=12/15#

Given #v = 12/15#, we have to simplify the fraction. A common denominator is #3#, thus we divide the numerator and denominator by 3. Resulting in #v=4/5#.

Hope this helps :)

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