How do you find the product of $(2 m + 2) (3 m - 3)$ $(2m+2)(3m-3)$ ?

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How do you find the product of $(2 m + 2) (3 m - 3)$ $(2m+2)(3m-3)$ ?

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Answer 1 · 2017-04-11T12:59:27

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(2 m + 2) (3 m - 3)$ $(color(red)(2m) + color(red)(2))(color(blue)(3m) - color(blue)(3))$ becomes:

$(2 m \times 3 m) - (2 m \times 3) + (2 \times 3 m) - (2 \times 3)$ $(color(red)(2m) xx color(blue)(3m)) - (color(red)(2m) xx color(blue)(3)) + (color(red)(2) xx color(blue)(3m)) - (color(red)(2) xx color(blue)(3))$

$6 m^{2} - 6 m + 6 m - 6$ $6m^2 - 6m + 6m - 6$

$6 m^{2} - 0 - 6$ $6m^2 - 0 - 6$

$6 m^{2} - 6$ $6m^2 - 6$

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How do you find the product of $(2 m + 2) (3 m - 3)$ $(2m+2)(3m-3)$ ?

1 Answer

Explanation:

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How do you find the product of (2m+2)(3m-3)(2m+2)(3m−3)(2m+2)(3m-3)?

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Explanation:

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How do you find the product of $(2 m + 2) (3 m - 3)$ $(2m+2)(3m-3)$ ?