If #f(x)=-(x-4)^2-3#, on what interval(s) is #f(x)# increasing?
2 Answers
Apr 10, 2017
(-infinity, 4)
Explanation:
To know where f(x) is increasing then we need to see where the derivaitve is +
f'(x)=
This hits 0 at x=4
For x<4: the derivative is positive therefore the function is increasing.
For x>4: the derivative is negative therefore decreasing.
So for (-infinity, 4) the function is increasing.
Apr 10, 2017
Explanation:
To determine the interval that f(x) is increasing.
#• " increasing when " f'(x) > 0#
#f'(x)=-2(x-4)larrcolor(red)" using chain rule"#
#"solve " -2(x-4)> 0#
#rArr-2x+8>0#
#rArrx<4#
#" interval is " (-oo,4)#
graph{-(x-4)^2-3 [-8.89, 8.89, -4.445, 4.44]}
