In the equation $x + y = 5$ $x+y=5$ , the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

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In the equation $x + y = 5$ $x+y=5$ , the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

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Answer 1 · 2017-04-08T19:41:10

$y \in {0, 1, 2}$ $y ∈ {0,1,2}$

Explanation:

If $2 < x < 6$ $2< x <6$ , it means that $x \in {3, 4, 5}$ $x ∈ {3,4,5}$ .

For x = 3
$3 + y = 5 \Rightarrow y = 2$ $3+y=5 =>y = 2$
For x = 4
$4 + y = 5 \Rightarrow y = 1$ $4+y=5 =>y = 1$
For x = 5
$5 + y = 5 \Rightarrow y = 0$ $5+y=5 =>y = 0$

Therefore $y \in {0, 1, 2}$ $y ∈ {0,1,2}$

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In the equation $x + y = 5$ $x+y=5$ , the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

In the equation x+y=5x+y=5x+y=5, the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?

1 Answer

Explanation:

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In the equation $x + y = 5$ $x+y=5$ , the value for x is a whole number greater than 2 but less than 6. How do you determine the possible solutions for y?