Question #04d04

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Answer 1 · 2017-04-07T17:33:49

2d and 3f does not exist

Principal quantum number n = 1, 2, 3, 4

Azimthual quantum number l =(n - 1) = 0 for s, 1 for p, 2 for d , 3 for f

Magnetic quantum number m = (-l, 0 + l)

For $n = 1$ $n = 1$ Magnetic quantum number $m$ $m$ is $0 = 1 s$ $0 = 1s$ orbital

For $n = 2$ $n = 2$ Magnetic quantum number $m$ $m$ is $(- l, 0 + l) = 2 p$ $(-l, 0 + l) = 2p$

For $n = 3$ $n = 3$ Magnetic quantum number $m$ $m$ is $(- 2, - l, 0 + l, + 2) = 3 d$ $(-2, -l, 0 + l, +2) = 3d$

for $n = 4$ $n = 4$ magnetic quantum number $m$ $m$ is $(- 3, - 2, - 1, 0, 1, 2, 3) = 4 f$ $(-3,-2,-1,0,1,2,3) = 4f$

$2 d$ $2d$ and $3 f$ $3f$ do not exist