Question #904a3

1 Answer
Sarita Rana
Apr 3, 2017

K = #1.5# x #10^2#

Explanation:

#CO(g)# + #2H_2 (g)# ⇌#CH_3OH(g)#
Kp = #2.26# x #10^4#

where K = #2.26# x #10^4# at #298# K.
If we were to divide the coefficients of above reaction equation by #2#, we would get the following equation:

#1/2 CO(g)# + #H_2 (g)# ⇌#1/2 CH_3OH(g)#

Now K =#[CH_3OH(g)]"^0.5#/[#CO(g)^0.5#]. [#H_2 (g)#]

threfore
K= √(kp)...........................square root of Kp
K = √ (#2.26# x #10^4#)
K = #150.33#
K = #1.5# x #10^2#

Related questions
See all questions in Equilibrium Constants
Impact of this question
4148 views around the world
You can reuse this answer
Creative Commons License