How do you divide $\frac { \frac { 20x ^ { 3} y } { 7m n ^ { 2} } } { \frac { 5x ^ { 5} y ^ { 3} } { 14n ^ { 5} } }$ ?

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Answer 1 · 2017-03-29T17:48:42

$(8n^3)/(x^2y^2m)$

You can write the above as:
$(20x^3y)/(7mn^2)*(14n^5)/(5x^5y^3)$

And that will multiply together as:
$(20x^3y)/(7mn^2)*(14n^5)/(5x^5y^3)=(280x^3yn^5)/(35x^5y^3mn^2)=(8n^3)/(x^2y^2m)$

How do you divide \frac { \frac { 20x ^ { 3} y } { 7m n ^ { 2} } } { \frac { 5x ^ { 5} y ^ { 3} } { 14n ^ { 5} } }\frac { \frac { 20x ^ { 3} y } { 7m n ^ { 2} } } { \frac { 5x ^ { 5} y ^ { 3} } { 14n ^ { 5} } }?