15g of copper(ii) chloride reacts with 20g of sodium nitrate. Calculate the mass of sodium chloride formed?

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15g of copper(ii) chloride reacts with 20g of sodium nitrate. Calculate the mass of sodium chloride formed?

I calculated the answer to be around 11.7g. Can someone help verify this?

2 Answers

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Answer 1 · 2017-03-29T11:22:59

12.15 grams

Explanation:

I got elemental weights as (Na=22.99 grams; Cu=63.55 grams; Cl=31.45 grams; N=14.01 grams; O=16 grams). The answer (Mass of sodium chloride after reaction) is 12.15 grams

Answer 2 · 2017-03-29T17:35:24

$N a C l$ $NaCl$ formed = $13.03 g$ $13.03 g$

Explanation:

$C u C l_{2}$ $CuCl_2$ + $2 N a N O_{3}$ $2NaNO_3$ ------------> $2 N a C l$ $2NaCl$ + $C u {(N O_{3})}_{2}$ $Cu(NO_3)_2$

no. of moles of $C u C l_{2}$ $CuCl_2$ = $15 g$ $15g$ / $134.45$ $134.45$ g.mol -1 = $0.1115$ $0.1115$ moles ..............(1)

no. of moles of $N a N O_{3}$ $NaNO_3$ = $20 g$ $20g$ / $84.99$ $84.99$ g.mol -1 = $0.2353$ $0.2353$ moles........(2)

According to equation
1 mole of $C u C l_{2}$ $CuCl_2$ produces $N a C l$ $NaCl$ = $2$ $2$ moles
so, $0.1115$ $0.1115$ moles of $C u C l_{2}$ $CuCl_2$ will produce $N a C l$ $NaCl$ = $2$ $2$ x $0.1115$ $0.1115$ moles = $0.223$ $0.223$ moles ........(3)

2 mole of $N a N O_{3}$ $NaNO_3$ produces $N a C l$ $NaCl$ = $2$ $2$ moles
so, $0.2353$ $0.2353$ moles of $N a N O_{3}$ $NaNO_3$ will produce $N a C l$ $NaCl$ = $2$ $2$ x $0.2353$ $0.2353$ moles...........(4)

$0.1115$ $0.1115$ moles of $C u C l_{2}$ $CuCl_2$ produces lesser number of moles of $N a C l$ $NaCl$ . hence $C u C l_{2}$ $CuCl_2$ is limiting reagent..................(5)

Therefore mass of $N a C l$ $NaCl$ produced = $0.223$ $0.223$ moles.......(6)
Molar mass of $N a C l$ $NaCl$ = $58.44$ $58.44$ g/mol
mass of $N a C l$ $NaCl$ = $0.223$ $0.223$ moles x $58.44$ $58.44$ g/mol = $* 13.03 * g$ $**13.03** g$

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15g of copper(ii) chloride reacts with 20g of sodium nitrate. Calculate the mass of sodium chloride formed?

I calculated the answer to be around 11.7g. Can someone help verify this?

2 Answers

Explanation:

Explanation:

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