How do you evaluate #\frac { 6+ i } { 2- 3i } =#?

1 Answer
Scott F.
Mar 27, 2017

#(9-20i)/13#

Explanation:

Multiply the fraction by #1# in the form of #(2+3i)/(2+3i)# (#2+3i# is the complex conjugate of the denominator) to get #i# out of the denominator.

#((6+i)(2+3i))/((2-3i)(2+3i))#

Multiply out and combine like terms, keeping in mind that #i^2="-"1#

#(12+18i+2i-3)/(4+6i-6i+9)=(9-20i)/13#

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