How do you solve #k^ { 2} + 2= 67#?

2 Answers
Aritra G. · MathFact-orials.blogspot.com
Mar 26, 2017

We've got #k^2 + 2 = 67#

#implies k^2 = 67 - 2#
#implies k^2 = 65#

Thus, #k = +(65)^(1/2)# and #k = -(65)^(1/2)#

Sena Dzirasa · MathFact-orials.blogspot.com
Mar 26, 2017

#k = +-sqrt65#

Explanation:

Group like terms by subtracting 2 from both sides of the equation.
#k^2 = 67 - 2#

Simplify
#k^2 = 65#

Take the square root of both sides. Remember when you take the square root, it becomes plus or minus (#+-#). Because either the positive or negative squared will give the positive figure.

#sqrt(k^2) = +-sqrt65#

#k = +-sqrt65#

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