How do you solve #|d - 2| + 5= 13#?

1 Answer
Jim G.
Mar 26, 2017

#d=-6" or " d=10#

Explanation:

Isolate the #color(blue)"absolute value function"# by subtracting 5 from both sides of the equation.

#|d-2|cancel(+5)cancel(-5)=13-5#

#rArr|d-2|=8#

There are 2 solutions when the bars are cleared.

#d-2=color(red)(+-8)#

#color(blue)"Solve: " d-2=color(red)(+8)#

add 2 to both sides.

#dcancel(-2)cancel(+2)=8+2rArrd=10#

#color(blue)"Solve: " d-2=color(red)(-8)#

#rArrd=-8+2=-6#

#color(blue)"As a check"#

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

#d=-6to|-6-2|+5=|-8|+5=8+5=13#

#d=10to|10-2|+5=|8|+5=8+5=13#

#rArrd=-6" or "d=10" are the solutions"#

Related questions
Impact of this question
326 views around the world
You can reuse this answer
Creative Commons License