Question #fff79

#x=-y^2+y#

#x=y^2-3#

#x=-4#

#V=piint_(-1)^(1.5)[(-y^2+y-(-4))^2-(y^2-3-(-4))^2]dy#

#=(875pi)/32#

#= 85.90292412#

"Find the volume of the solid obtained by rotating the region bounded by the curves #y=x^3#, the #x#-axis and the lines #x=1# and #x=2# turn around the x-axis."

#V=piint_1^2(x^3)^2dx#

#=piint_1^2(x^6)dx#

#=pi[1/7x^7]_1^2#

#=2^7/7-1/7#

#=(255pi)/7#