How do you factor $2 m^{3} p^{2} - 16 m p^{2} + 8 m p$ $2m^3p^2-16mp^2+8mp$ ?

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Answer 1 · 2017-03-17T05:45:24

Start with Greatest Common Factor

$2 m^{3} p^{2} - 16 m p^{2} + 8 m p$ $2m^3p^2-16mp^2+8mp$

Factor out 2mp: $2 m p (m^{2} p - 8 p + 4)$ $2mp(m^2p-8p+4)$

How do you factor 2m^3p^2-16mp^2+8mp2m3p2−16mp2+8mp2m^3p^2-16mp^2+8mp?