Given $g(x) = -2x^2 - 9$ how do you find g(3)?

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Answer 1 · 2017-03-16T00:39:58

$g(3)=-27$

You would substitute 3 for each x...
$-2(3)^2-9$
$-2(9)-9$
$-18-9$
$-27$
$g(3)=-27$

Answer 2 · 2017-03-16T00:41:14

$g(3)=-27$

Given:

$g(x)=-2x^2-9$

Solve if $g(x)=g(3)$

Substitute $3$ for $x$ .

$g(3)=-2(3)^2-9$ $larr$ parentheses and exponents first

$g(3)=-2xx9-9$ $larr$ multiply $-2xx9$

$g(3)=-18-9$

$g(3)=-27$

Given g(x) = -2x^2 - 9g(x) = -2x^2 - 9 how do you find g(3)?