How do you solve #\frac { 1} { x } + \frac { 1} { 3} = \frac { 8} { 3} x#?

1 Answer
hereyougo
Mar 15, 2017

#x=(1+-sqrt(97))/16#

Explanation:

First you would subtract #1/3# from both sides
this would give you #1/x=(8x-1)/3#
then you would cross multiply to get #3=8x^2-x#
subtract 3 to get #8x^2-x-3#
use the quadratic formula:
#(-(-1)+-sqrt((-1)^2-4(8)(-3)))/16#
that simplifies to #(1+-sqrt(97))/16#

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