A triangle has sides A, B, and C. The angle between sides A and B is (pi)/2π2 and the angle between sides B and C is pi/12π12. If side B has a length of 54, what is the area of the triangle?

1 Answer
Mar 15, 2017

The area of the triangle is about 390.69 units^2390.69units2

Explanation:

since pi/2=90π2=90degrees we know this triangle is right
we can find the side of A by saying tan(pi/12)=A/54tan(π12)=A54
then rearrange the equation to get A=54tan(pi/12)A=54tan(π12)
this gives you A=14.47A=14.47
then you can use the formula for the area of a triangle which is
1/212(base)(height)
so the equation would be 1/2(54)(14.47)12(54)(14.47)
This is equal to (390.69)