What is the vertex of y = 2(x - 3)^2 + 1?

1 Answer
Smartine201
Mar 8, 2017

(3,1)

Explanation:

The answer happens to be in the equation without any work needed!

This equation is already in vertex form. The equation for vertex form is y=a(x-h)^2+k

In this equation, (h,k) is the vertex. When you look at your equation: y=2(x-3)^2+1, the h,k is (3,1).

Note: in vertex form, there is a negative sign in front of the h, so you must take whatever h value there is an make is opposite. Thus, your vertex is (3,1) and not* (-3,1).

Check your answer with a graph!
graph{2(x-3)^2+1 [-3.354, 6.646, -1.18, 3.82]}

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