How do you combine like terms in $(23x ^ { 2} - 27) - ( - 31x ^ { 2} - 41) - ( 22x ^ { 2} + 14)$ ?

Question

1550 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-08T22:30:11

$32x^2$
just add the coefficients of the same order

$(23x^2-27)-(-31x^2-41) -(22x^2+14)$

$23x^2-27 +31x^2+41-22x^2-14$

$23x^2+31x^2-22x^2-27+41-14$

$(23+31-22)x^2 -27+41-14$

$32x^2+14-14$

= $32x^2$

Answer 2 · 2018-08-06T02:42:47

$32x^2$

We can distribute the negatives to now obtain the expression

$23x^2-27+31x^2+41-22x^2-14$

Now, we just combine the terms with the same degree with each other. We get

$32x^2-27+41-14$

The constants cancel out, and we're left with

$32x^2$

Hope this helps!

How do you combine like terms in (23x ^ { 2} - 27) - ( - 31x ^ { 2} - 41) - ( 22x ^ { 2} + 14)(23x ^ { 2} - 27) - ( - 31x ^ { 2} - 41) - ( 22x ^ { 2} + 14)?