How do you factor -6x^2+31x-35?

1 Answer
jeffwwally
Mar 3, 2017

(3x-5)(2x-7)

Explanation:

I started by factoring out a negative one.
-6x^2+31x-35
-1(6x^2-31x+35)

From there, you can split the middle term to accommodate both terms and get the same internal expression. (Some guess and check involved)
6x^2-21x-10x+35
3x(2x-7)-5(2x-7)

From there you combine them to get
(3x-5)(2x-7)
and there is your factored form.

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
5710 views around the world
You can reuse this answer
Creative Commons License