How do you find \int _ { - 2} ^ { 0} ( 2x + 5) d x?
2 Answers
Mar 2, 2017
6 units squared.
Explanation:
Using the chain rule, the integral is
=
Thus the answer is
Mar 3, 2017
int_(-2)^0 \ 2x + 5 \ dx = 6
Explanation:
graph{2x+5 [-9.58, 10.42, -2.52, 7.48]}
The integrand is
With
x=0 \ \ \ \ \=> y=5
x=-2 => y=1
The area is a trapezium with
Hence,
int_(-2)^0 \ 2x + 5 \ dx = 1/2(5+1)(2) = 6