What is the acceleration of a #0.30# kilogram ball that is hit with a force of #25# #N#?

1 Answer
Ryuu
Feb 27, 2017

The acceleration of the ball is #83.333 m/s^2# [forward].

Explanation:

So the equation we are using is #F_"NET"=ma#
=> Where #F_"NET"# is the net force in #N#.
=> Where #m# is the mass in #kg#.
=> Where #a# is the acceleration in #m/s^2#.

Before we calculate the acceleration, we have to make some things clear and establish some other things.

  1. The force of friction, #F_"F"#, will be ignored.
  2. No direction is specified, however, a force is applied to the object. The movement produced will be referred to as motion in a positive direction.

We are going to rearrange the equation of #F_"NET"=ma#, so we can get the acceleration: #a=F_"NET"/m#

#a=F_"NET"/m#

#=25/0.30#

#=83.333#

The acceleration of the ball is #83.333 m/s^2 "[forward]"#.

Now that may seem like a lot, and that's because you are applying a lot of force to a relatively small (and lightweight) object.

Hope this helps :)

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