How do you multiply $(3x-2)^2$ ?

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Answer 1 · 2017-02-23T04:49:24

$9x^2-12x+4$

$(3x-2)^2$ can be expanded to $(3x-2)(3x-2)$
From here you can use the FOIL method to expand.

The "first" would be $3x*3x=9x^2$
The "outside" would be $3x*-2=-6x$
The "inside," $-2*3x=-6x$
And the "last," $-2*-2=4$

Putting the terms together you get
$9x^2-6x-6x+4$

And combining like terms
$9x^2-12x+4$

How do you multiply (3x-2)^2(3x-2)^2?