What is the sum of $\frac{y}{3}$ $y/3$ and $\frac{4 y}{9}$ $(4y)/9$ when $y = 7$ $y=7$ ?

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What is the sum of $\frac{y}{3}$ $y/3$ and $\frac{4 y}{9}$ $(4y)/9$ when $y = 7$ $y=7$ ?

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Answer 1 · 2017-02-20T05:25:25

5 $\frac{4}{9}$ $\frac {4} {9}$ or $\frac{49}{9}$ $\frac {49} {9}$

Explanation:

So first you make the fractions $\frac{y}{3}$ $\frac {y} {3}$ and $\frac{4 y}{9}$ $\frac {4y} {9}$ have equal denominators. You do this by multiplying the denominator and numerator by 3 for the fraction $\frac{y}{3}$ $\frac {y} {3}$ . This gives you $\frac{3 y}{9}$ $\frac {3y} {9}$ . Then you add $\frac{3 y}{9}$ $\frac {3y} {9}$ and $\frac{4 y}{9}$ $\frac {4y} {9}$ together to get $\frac{7 y}{9}$ $\frac {7y} {9}$ . Finally, you substitute 7 for $y$ $y$ to get $\frac{7 \cdot 7}{9}$ $\frac {7*7} {9}$ . This gives you $\frac{49}{9}$ $\frac {49} {9}$ or putting into mixed fraction gives you 5 $\frac{4}{9}$ $\frac {4} {9}$ .

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What is the sum of $\frac{y}{3}$ $y/3$ and $\frac{4 y}{9}$ $(4y)/9$ when $y = 7$ $y=7$ ?

1 Answer

Explanation:

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What is the sum of $\frac{y}{3}$ $y/3$ and $\frac{4 y}{9}$ $(4y)/9$ when $y = 7$ $y=7$ ?