How do you factor completely 12x^3 - 3xy^2?

2 Answers
Feb 19, 2017

3x(2x+y)(2x-y)

Explanation:

12x^3-3xy^2

take out all common factors

3x(4x^2-y^2)

use difference of squares

3x(2x+y)(2x-y)

Feb 19, 2017

To factor, we have to divide out common factors in each term. Let's first write out the factors:

12x^3 = 4*3*x*x*x

-3xy^2 = 3*-1*x*y*y

Now look for the factors that each term share. We see that there is a 3 and an x that is found in each list. Now we have to take this out of each list.

(3*x)(4*x*x)

(3*x)(-1*y*y)

Remember that these were being subtracted, so rewrite:

(3*x)[(4*x*x) -(1*y*y)]

Simplify.

(3x)(4x^2-y^2)

Use difference of squares to simplify further.

(3x)(2x-y)(2x+y)