What is the disproportionation reaction of $H_{3} P O_{3}$ $H_3PO_3$ ?

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What is the disproportionation reaction of $H_{3} P O_{3}$ $H_3PO_3$ ?

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Answer 1 · 2017-02-18T17:02:09

$4 H_{3}$ $4H_3$ $P O_{3}$ $PO_3$ ----------> $3 H_{3}$ $3H_3$ $P O_{4}$ $PO_4$ + $P H_{3}$ $PH_3$

Explanation:

Disproportionation is a type of redox reaction where an element from a reaction undergoes both oxidation and reduction to form two different types of products. Similarly in case of $H_{3}$ $H_3$ $P O_{3}$ $PO_3$ gives two products on diproportionation on heating.

On heating $H_{3}$ $H_3$ $P O_{3}$ $PO_3$ it undergoes disproportionation reaction to give ortho phosphoric acid and phosphine.
$4 H_{3}$ $4H_3$ $P O_{3}$ $PO_3$ ----------> $3 H_{3}$ $3H_3$ $P O_{4}$ $PO_4$ + $P H_{3}$ $PH_3$

Each element undergoes oxidation and reduction:

Oxidation half reaction =
$H_{3}$ $H_3$ $P O_{3}$ $PO_3$ ----------> $H_{3}$ $H_3$ $P O_{4}$ $PO_4$

Reduction half reaction
$H_{3}$ $H_3$ $P O_{3}$ $PO_3$ ----------> $P H_{3}$ $PH_3$

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What is the disproportionation reaction of $H_{3} P O_{3}$ $H_3PO_3$ ?

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