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How do you determine if #f(x) = 2x^2 - 2# is an even or odd function?

1 Answer

Feb 18, 2017

Function is even

Explanation:

For an even function, #f(x) = f(-x)#. You can think of it as reflective symmetry about the y axis.

For an odd function, #f(x) = - f(-x)#. You can think of symmetry via a 180 rotation about the Origin.

Here: #f(-x) = 2 (-x)^2 - 2 = 2 x^2 - 2 = f(x)#.

So this function is even.

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